-10x^2=-630

Solution for -10x^2=-630 equation:

-10x^2=-630

We move all terms to the left:

-10x^2-(-630)=0

We add all the numbers together, and all the variables

-10x^2+630=0

a = -10; b = 0; c = +630;
Δ = b2-4ac
Δ = 02-4·(-10)·630
Δ = 25200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25200}=\sqrt{3600*7}=\sqrt{3600}*\sqrt{7}=60\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{7}}{2*-10}=\frac{0-60\sqrt{7}}{-20}
=-\frac{60\sqrt{7}}{-20}
=-\frac{3\sqrt{7}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{7}}{2*-10}=\frac{0+60\sqrt{7}}{-20}
=\frac{60\sqrt{7}}{-20}
=\frac{3\sqrt{7}}{-1}
$